文档介绍：导体载流量的计算口诀Chapteriithecalculationofthetrafficf1owofconductorsUSES:theamountoftraffic(safetycurrent),youcandirectlyworkoutthetable・Wirecarryingcapacityandloadoftheconductorsurface,alsowiththeconductormaterial(aluminumorcopper),model(insulatedwireorbarewire,etc・),layingmethod(Mingfuorweartube,etc・)andtemperature(25degreesormore)andsoon,influenceofmanyfactors,plicated・10,5,1,0,0,,five,three,five,four,three・Seven,zero,y-five,%:thekeyisthealuminuminsulatedwire,whichisappliedtotheambienttemperatureof25degrees・Iftheconditionisdifferent,(current,Ann)isnotdirectlypointedout,but〃byacertainmultipleofthecrosssection〃.Todothis,youshouldfamiliarizeyourselfwiththesectionofthewire,(sqmm),1,,,4,6,10,16,25,35,50,50,50,50,150...,;-insulatedconductorflux(Ann)ordingtothenumberofsections・TheArabicdigitslrepresentationofthecrosssection(squaremm)inthetipisamultipleofChinesecharacters・Thelinkbetweenthecrosssectionandthemultipleisasfollows:.・10,16-25,35-50,70-95,120...ThreetimesasmuchasfivetimesasmuchasfourtimesasmuchastwoandahalftimesasmuchastwotimesNowandagaintheformulacontrolmaybemoreclear・Originallyunderthe〃tenfive"referstothesectionbelowfrom10,carryingcapacityisthenumberofsectionfivetimes・The"100totwo"(readonehundredandtwo)meansmorethan100sectionsofthesection,whichistwicethenumberofsections・Thesection25and35arefourtimesandthreefold・Thisisthe"tip25,35."Thecrosssectionis70,・Fromtheabovearrangement,youcanseethatinadditionto10andabove,t