文档介绍：(1)double fun(int n)
(2)s=s+(double)a/b;
(1)for(i=0;str[i];i++)
(2)if(substr[k+1]== '\0')
(1)t = *x ; *x = y ;
(2)return(t) ;或return t;
(1)t=a;a=b;b=t;
(2)return(b);或return b;
(1)*t=0;
(2)if(d%2!=0)或if(d%2==1)
(1)去掉分号
(2)case 1:case 2:return 1;
(1)b[k]=*p;
(2)b[k]=' ';k++;
(1)if(( tt[i]>='a')&&( tt[i] <= 'z'))
(2)tt[i]-=32;
(1)for (j = i + 1; j < 6; j++)
(2)*(pstr + i) = *(pstr + j) ;
(1)long k=1;
(2)num /=10;
(1)float k;
(2)if(*a< *c)
(1) int k=0;
(2)while (*p||*q)
(1)long s=0, t=0;
(2)t=t/10;
(1)a2=k/10;
(2)return i;
(1)void fun(char *a)
(2)printf("%c" ,*a) ;
(1)n= *p-'0';
(2)n=n*8+*p-'0';
(1)if(d%2==0)
(2)s/=10;
(1)while((high>=2) && (n<10))
(2)yes=0; break;
(1)s[j++]=s[i];或{s[j]=s[i];j++;}
(2)s[j]= '\0';
(1)void fun(long s,long *t)
(2)sl=sl*10;
(1)double f(double x)
(2)return s ;
(1)fun(int x,int y, int z)或int fun(int x,int y,int z)
(2)return j;
(1)while( *r)
(2)*a=*r;a++;r++;
(1)char *fun(char (*sq)[M])
(2)return sp;
(1)int fun(int a[],int m)或fun(int a[],int m)
(2)else if(m>a[mid])
(1)void fun(long s,long *t)
(2)while(s>0)
(1)double fun(double a,double x0)
(2)if(fabs(x1-x0)>=)
(1)p=j ;
(2)p=i;
(1)#define FU(m,n) (m)/(n)
(2)return (value);
(1)n=strlen( aa ) ;
(2)ch=aa[i];
(1)k++;
(2)if(m==k)
(1)void fun ( char *s , char *t )
(2)t[2*d]='\0';或t[d+i]='\0';或t[2*d]=0;或t[d+i]=0;
(1)for(i=2;i<=m;i++)
(2)y+=/(i*i);或y+=(double)/(i*i)
(1)if(i%2||s[i]%2==0) 或 if(i%2 !=0 || s[i]%2==0)
(2)t[j]='\0'; 或 t[j]=0;
(1)if(p==n) return -1;
(2)a[i]=a[i+1];
(1)r=t;
(2)应填:r=t;或r=&t[0];
(1)while(fabs(t)>=num)
(2)t=s/n;
(1)while(*s)或while(*s!='\0')
(2)s++;
(1)s[j++]=s[i];
(2)s[j]= '\0';
(1)double sum=;
(2)sum/=c;
(1)while (*w)
(2)if ( *r ==*p )
(1)t=calloc(m,sizeof(STU));
(2)t[k]=b[j];
(1)double r ;
(2)while (fabs(n-m) >)
(1)int i, sl;
(2)t[i]=s[sl-i-1];
(1)t=;
(2)return(s*2);
(1)for(i=j+1;i<n;i++)
(2)p=i;
(1)if( n==0)
(2)result *=n--;或{result *=n; n--;}
(1)s=s +(doub