一元一次方程计算题37道带答案.doc

文档介绍：(x-)+=--10(10-x)=1004(x+2)=5(x-2)120-4(x+5)=2515x+863-65x=543(x-2)+1=x-(2x-1)11x+64-2x=100-+x-=0x-+=80820-16x=×8(x-6)×7=2x3x+x=+=-3x=(x-)=+=-=(x-2)-3(4x-1)=9(1-x)11x+64-2x=100-9x15-(8-5x)=7x+(4-3x)3(x-7)-2[9-4(2-x)]=222(x-2)+2=x+130x-10(10-x)=1004(x+2)=5(x-2)120-4(x+5)=2815x+854-65x=543(x-2)+1=x-(2x-1)11x+64-2x=100-+x-=0(x-6)×7=2x-23x+x=-3x=(x-)=+=-==5x-3x+5=8答案x=6x=5x=18x===3/2x=2x======11x=2x==5x=3x=-10x=2x=-3x=-11x=3x=50x=18x=18x=16x=3/2x=2x==8x=9/2x=2x=10x=5x==1x=3