文档介绍：一元一次方程计算题7(2x-1)-3(4x-1)=4(3x+2)-1;(5y+1)+(1-y)=(9y+1)+(1-3y);2(x-2)+2=x+12(x-2)-3(4x-1)=9(1-x)x/3-5=(5-x)/22(x+1)/3=5(x+1)/6-1(1/5)x+1=(2x+1)/4(5-2)/2-(4+x)/3=1x/3-1=(1-x)/2(x-2)/2-(3x-2)/4=-111x+64-2x=100-9x15-(8-5x)=7x+(4-3x)3(x-7)-2[9-4(2-x)]=223/2[2/3(1/4x-1)-2]-x=22(x-2)-3(4x-1)=9(1-x)11x+64-2x=100-9x15-(8-5x)=7x+(4-3x)3(x-7)-2[9-4(2-x)]=223/2[2/3(1/4x-1)-2]-x=22(x-2)+2=x+(2x-1)-3(4x-1)=4(3x+2)-12.(5y+1)+(1-y)=(9y+1)+(1-3y)3.[(-2)-4]=x+%+(1-20%)(320-x)=320×40%(x-2)+2=x+(x-2)-3(4x-1)=9(1-x)+64-2x=100--(8-5x)=7x+(4-3x)(x-7)-2[9-4(2-x)]=[2/3(1/4x-1)-2]-x=+1-2x=3x--4=2y+*13==+863-65X=*55=(x+2)+4=(x+4)=(x-5)=+8=2(x-1)(x+3)=9+(x/2+1)=(x+6)=+x=2(x-1/2)+3(1-x)=-+x-2(x-1)=-5=(5-x)/(x+1)/3=5(x+1)/6-129.(1/5)x+1=(2x+1)/430.(5-2)/2-(4+x)/3=115x-8(5x+)=18*+(x-2)-3(4x-1)=9(1-x)+64-2x=100--(8-5x)=7x+(4-3x)(x-7)-2[9-4(2-x)]=[2/3(1/4x-1)-2]-x=(x-2)+2=x+(x-)+=--10(10-x)=(x+2)=5(x-2)-4(x+5)=+863-65x=(x-2)+1=x-(2x-1)+64-2x=100-+x-=-+=-16x=×817.(x-6)×7=+x=+=-3x=(x-)=+=-=-=-(1-)x=803x/2+3x/2=743x+7=32-2x53x+5(138-x)=54063