文档介绍：整式训练专题训练201511041归纳出去括号的法则吗?:(1)();(2)();(3)-()+();(4)()-().?若有错,请改正:(1)a2-(2a)(2)-()+(1)2-2a;1.(3)(y-x)2=(x-y)2(4)(-y-x)2=(x+y)2(5)(y-x)3=(x-y):(1)(23y)+(54y);(2)(8a-7b)-(4a-5b);(3)(2a)+2(2b);(4)3(54)-(35);(5)(83y)-(43)+2z;(6)-5x2+(58x2)-(-12x2+4x)+2;(7)2-(1)+(122);(8)3a22-(2a2-2a)+(3a2)。作业:,在上填上“+”号或“-”号:(1)();(2)();(3)()(),则3=,:(1)3(2); (2)32(32z).(3)34(24a); (4)(23y)-3(42y).:(1)2a-3[4a-(3a)];(2)3-2c[-4a+(3b)].拔高题:-[2(3y)-3(2y)]的结果是().; ; C.-5122; -:3,求{[x2-(1)]}-,与a-b-c的值不相等的是()-(b+c)-(b-c)C.(a-b)+(-c)D.(-c)+(-b+a)-[0-(2p-q)]的结果是()A.-2p-qB.-2p+-+,正确的是()-(2b-3c)=a-2b--(3x2+2x-1)=x3-3x2-2x-+(-2y+1)=2y2-2y+1D.-(2x-y)-(-x2+y2)=-2x+y+x2+:a+(b-c)=;(a-b)+(-c-d)=;-(a-b)-(-c-d)=;5x3-[3x2-(x-1)]=..(1)()=x-y-z()(2)-(x-y+z)=-x+y-z()(3)x-2(y-z)=x-2y+z()(4)-(a-b)+(-c-d)=-a+b+c+d():-(2m-3);n-3(4-2m);(1)16a-8(3b+4c);(2)-(x+y)+(p+q);(3)-8(3a-2+4);(4)4(+p)-7(n-2q).(5)8(y-x)2-(x-y)2-4(-y-x)2-3(x+y)2+2(y-x),再合并同类项:-2n-(3n-1);a-(5a-3b)+(2b-a);-3(2s-5)+6s;1-(2a-1)-(3a+3);3(-+2a)-(3a-b);14(-2a)+3(6a-2).-︱-[a-(b-c)]︱去括号后的结果应为()+b+-.-a+b--b-(3-)-︱-3︱的结果为().---,合并同类项;6a2-2-2(3a2-);2(2a-b)-[4b-(-2a+b)]9a3-[-6a2+2(a3-a2)];2t-[t-(t2-t-3)-2]+(2t2-3t+1).,并求出代数式25+3a-{11a-[a-10-7(1-a)]}的值,你能从中发现什么?