文档介绍：编程实现,输入一个人民币小写金额值,转化为大写金额值输出。先实现基本功能,,可以输出“壹佰零拾零万贰仟三佰零拾零元玖角零分”。#include<>main(){doubler,y;intx,m,n,j,i,k,flag=0;intstr1[10]={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};intstr2[14]={"仟","佰","拾","亿","仟","佰","拾","萬","仟","佰","拾","元","角","分"};charstr3[30];printf("请输入金额(范围小于千亿):\n");scanf("%lf",&r);if(r>=00)printf("输入的数超出范围,请重新输入\n");y=r-(int)r;/*y为小数部分*/x=(int)r;/*x为整数部分*/for(i=0;i<=11;i++)/*整数部分*/{m=(int)((int)x%10);str3[11-i]=m;x=(int)(x/10);}str3[12]=(int)(y*10);/*小数部分*/str3[13]=(int)(y*100)%10;for(k=0;k<=13&&flag==0;k++)/*判断最大位是多少*/ {if(str3[k]>0) {flag=1;n=k; } }for(j=n;j<=13;j++)printf("%s%s",str1[str3[j]],str2[j]);printf("\n");}2.(拓展题,分值25)编程实现,输入一个人民币小写金额值,转化为大写金额值输出。要求实现完善的功能,,应该输出“壹佰万贰仟三佰元零玖角整”。#include<>main(){doubler,y;intx,m,n,j,i,k,flag=0;intstr1[10]={"","壹","贰","叁","肆","伍","陆","柒","捌","玖"};intstr2[14]={"仟","佰","拾","亿","仟","佰","拾","萬","仟","佰","拾","元","角","分"};charstr3[30];printf("请输入金额(范围小于千亿):\n");scanf("%lf",&r);if(r>=00)printf("输入的数超出范围,请重新输入\n");y=r-(int)r;/*y为小数部分*/x=(int)r;/*x为整数部分*/for(i=0;i<=11;i++){m=(int)((int)x%10);str3[11-i]=m;x=(int)(x/10);}str3[12]=(int)(y*10);str3[13]=(int)(y*100)%10;if(y==0)/*当没有小数时的输出*/ {for(k=0;k<=13&&flag==0;k++)/*判断最大位是多少*/ {if(str3[k]>0) {flag=1;n=k; } }for(j=n;j<=11;j++)