文档介绍：一元一次不等式(1)??1?x5x3x?29?2x?1x?312??3???(1)(2)84233x?4≥—2)(4(3)3x+2<2x—531?mm(185()3(y+2)—1≥—2(y—1)<6)?23112????(>(7)8≤)2)2(x?3x?1)(x?x?2)?x3(?x1)(?x??225??二、解下列不等式,并将解集在数轴上表示出来:)(—<)(13x+22x823)((3)9+4x22x+3)<5x+1(≥—2x12?2xx?23x?5x??>0(5)(6))≤x+73—19)4((1?3222三、解答题6x?1?2x的值①大于取何值时,代数式-2;②不大于1-,最大的负整数是,最小的非负整数是。最小的自然数是,绝对值最小的整数,小于。5的非负整数是????6a3?5x?33x?a2?a=的方程的解是负数,求字母的取值范围;????7x?15?x?2??8632x?ax?的解,?a4的值。a3?2kx1?x2k?3k=________;,是关于____________.???6x??24x??7x的值为负数,?3?,?2y?6y4x?,若已知,2x?15x?1??1的非正整数解10.,???a?4?3ax2x?5a0??04xx?4?,?03a?1a2?41?a?a?2a.,?25??115x?2x?0?.,满足3x33y?9?y?4?y2?2y?3??14.,?2x1???为未知数?ax?x4?2xa的解的解15.,的,求也是不等式已知不等式6233取值范围.??a?34?ax??2a??3?x?a的解集,?y?2a?,?x?3y?1?5a?12xm2x?m?2x???,?1?2x?12x?1?32x?3?5???(1))()(23???34?8x?2?2xx?3?2x3???x1??x5??1??)?5x?23(x1????62?31(4))(5?x?x1??7?)?4?33((xx?4)??22?3?6x01x2???4????3??2?02?x?xx)(7)6(????84?3x?x?2?0?x3??:3(1?3x)5?3x?861???;?1?0?m的取值范围。.若不等式组无解,求3?x?m?0?x?3?x?3a的取值范围;的解集是4.,求?x?a?x?4?x?4b的取值范围。的解集是5.,求?x?b?8x?ay?8?a的解是正数?,方程组?4x?3y?6?3x?2y?4a?3??2x?3y?a?7a的取值范围。,求??x?y?0?x?a?2?aa≤