文档介绍:ΚƑܾ
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HUST Lab of Thermal Science & Engineering
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ΚƑܾ
2005-8-2 1
ΚƑܾ
ҔᏄҚ
HUST Lab of Thermal Science & Engineering
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2005-8-2 2
ΚƑܾ
ҔᏄҚ
HUST Lab of Thermal Science & Engineering
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2005-8-2 3
ΚƑܾ
ҔᏄҚ
HUST Lab of Thermal Science & Engineering
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1AQᇔRƑT̤ 2VW6X5
4 YZX ၘ
1 2 X1,2
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]
Q1,2 = Eb1 A1 X 1,2 − Eb2 A2 X 2,1
2005-8-2 4
ΚƑܾ
ҔᏄҚ
HUST Lab of Thermal Science & Engineering
2
^_`\abȉූ@(YZX
eǒ˫Z 5YZXe4I g3ǒސI h
A X XA
҈ 1 1 2 2 2 1
aȑ&ȏ? j҅ܖϤᇔސ
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m<ຐܖn҅AQᇔRW6(
WTp<ຐqV r࡚
ᇔ̤tu<R]vwxj҅yz
| n
X 1,1 + X 1,2 + X 1,3 + L + X 1,n = ∑ X 1,i = 1
i=1
2005-8-2 5
ΚƑܾ
ҔᏄҚ
HUST Lab of Thermal Science & Engineering
n
X + X + X + + X = X = 1 4
1,1 1,2 1,3 L 1,n ∑ 1,i 3 5
i=1
2 6
1 X1,1 = 0
gƑඥ h
1 1
4YZX *
1 X1,1
) P
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YZX}ͪI)YZX҈IQ7
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2005-8-2 6
ΚƑܾ
ҔᏄҚ
HUST Lab of Thermal Science & Engineering
A1Eb1 X1,2 = A1Eb1 X1,2a + A1Eb1 X1,2b
2a 2b
X 1,2 = X 1,2a + X 1,2b
1
3 ࢨ$
p
%&' dA 2
r
ϕϕϕ 2 ˍخ\V>6
n
< 2
dA 1 dA 2
ϕϕϕ dΩΩΩ
1
ᇔG ᇔR n1
]
dQ1,2 = dA1I1 cosϕ1dϖ 1 dA 1
2005-8-2 7
ΚƑܾ
ҔᏄҚ
HUST Lab of Thermal Science & Engineering
dQ1,2 = dA1I1 cosϕ1dϖ 1 p
dA 2
ޖ¡ȏY
r ϕϕϕ 2
2
ϕdϖ 1= dA 2cos 2 / r n2
ϕ
ϕϕϕ dΩΩΩ
cos 1 cosϕ 2
dQ = I dA dA n 1
1 1 r 2 1 2 1
ޖᇔG ᇔ¢(˫Z
dA 1
E
I = b
b π
tu<AQᇔR
dA 1
Q1 = πI1dA1
2005-8-2 8
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