文档介绍：By: Prof. Y. Peter Chiu
Material Management
~ HOMEWORK SOLUTION ~
#1
1
# 9
(b)
Week
MPS-end item
Component B ()
Component F
-Net. Req.
Time . Req.
Ans. →Planned Order Release
27 28 29 30 31 32 33 34 35
165 180 300 220 200 240
330 360 600 440 400 480
330 360 600 440 400 480
330 360 600 440 400 480
330 360 600 440 400 480
2
# 9
(c)
Week
MPS-end item
–Comp. B
Net Req. –Comp. E
Time Phased –Net Req.
– Comp. E
–Comp. G
Time Phased –Net Req.
Net Req. –Comp. G
Net Req. –Comp. I
Net Req. –Comp. H
Time Phased –Net Req.
Time Phased –Net Req.
Ans. → –Comp. I
Ans. → –comp. H
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
165 180 300 220 200 240
330 360 600 440 400 480
330 360 600 440 400 480
330 360 600 440 400 480
330 360 600 440 400 480
660 720 1200 880 800 960
660 720 1200 880 800 960
660 720 1200 880 800 960
660 720 1200 880 800 960
660 720 1200 880 800 960
660 720 1200 880 800 960
1980 2160 3600 2640 2400 2880
1980 2160 36002640 2400 2880
1980 2160 36002640 2400 2880
(d)
3
Month
Demand
1 2 3 4 5 6 7 8 9 10 11 12
6 12 4 8 15 25 20 5 10 20 5 12
Current Inventory : 4
An ending Inventory should be : 8
h = $ 1
k = $ 40
Month
Net. Demand
# 14
1 2 3 4 5 6 7 8 9 10 11 12
2 12 4 8 15 25 20 5 10 20 5 20
Starting in Period 1 :
C(1) = 40
C(2) = (40+12)/2 = 26
C(3) = [40+12+2(4)] /3 = 20
C(4) = [40+12+2(4)+3(8)] /4= 21 <stop>
∴
(a) Silver-Meal
4
Starting in Period 4 :
∴
Starting in Period 9 :
Starting in Period 6 :
C(1) = 40
C(2) = [40+15]/2 =
C(3) = [40+15+2(25)] /3 = 35 <stop>
C(1) = 40
C(2) = [40+20]/2 = 30
C(3) = [40+20+2(5)] /3 =
C(4) = [40+20+2(5)+3(10)] /4 = 25 <stop>
C(1) = 40
C(2) = [40+20]/2 = 30
C(3) = [40+20+2(5)] /3 =
C(4) = [40+20+2(5)+3(20)] /4 = <stop>
∴
∴
∴
∴ Using Silver- Meal ; y = [ 18 , 0 , 0 , 23 , 0 , 50 , 0 , 0 , 35 , 0 , 0 , 20 ]
# 14
(a) Silver-Meal
5
C(1) = 40 /2 = 20
C(2) = 52 /14 =
C(3) = 60 /18 =
C(4) = 84 /26