一元一次方程计算题.doc

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一元一次方程计算题
7(2x-1)-3(4x-1)=4(3x+2)-1;
(5y+1)+ (1-y)= (9y+1)+ (1-3y);
2(x-2)+2=x+1
2(x-2)-3(4x-1)=9(1-x)
x/3 -5 = (5-x)/2
2(x+1) /3=5(x+1) /6 -1
(1/5)x +1 =(2x+1)/4
(5-2)/2 - (4+x)/3 =1
x/3 -1 = (1-x)/2
(x-2)/2 - (3x-2)/4 =-1
11x+64-2x=100-9x
15-(8-5x)=7x+(4-3x)
3(x-7)-2[9-4(2-x)]=22
3/2[2/3(1/4x-1)-2]-x=2
2(x-2)-3(4x-1)=9(1-x)
11x+64-2x=100-9x
15-(8-5x)=7x+(4-3x)
3(x-7)-2[9-4(2-x)]=22
3/2[2/3(1/4x-1)-2]-x=2
2(x-2)+2=x+1
(2x-1)-3(4x-1)=4(3x+2)-1
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2.(5y+1)+ (1-y)= (9y+1)+ (1-3y)
3.[ (- 2)-4 ]=x+2
%+(1-20%)(320-x)=320×40%
(x-2)+2=x+1
(x-2)-3(4x-1)=9(1-x)
+64-2x=100-9x
-(8-5x)=7x+(4-3x)
(x-7)-2[9-4(2-x)]=22
[2/3(1/4x-1)-2]-x=2
+1-2x=3x-2
-4=2y+1
*13=5
=41
+863-65X=54
*55=27489
〔x+2〕+4=9
(x+4)=10
(x-5)=18
+8=2(x-1)
(x+3)=9+x
(x/2+1)=12
(x+6)=63
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+x=2(x-1/2)
+3(1-x)=-2
+x-2(x-1)=1
-5 = (5-x)/2
(x+1) /3=5(x+1) /6 -1