文档介绍：大学物理复****题(双语)
1. A particle moves along the x axis. Its position as a function of time is given by x=+ 2, wheon of the front of the train. We can find the acceleration of the train from the motion up to the point where the front of the train passes the worker: v 12 = v 02 + 2a (D – 0);
(25 m/s)2 = 0 + 2a (140 m – 0),
which gives a = m/s 2.
Now we consider the motion of the last car, which starts at – L , to the point where it passes the worker: v 22 = v 02 + 2a [D – (– L )]
= 0 + 2( m/s 2)(140 m + 75 m), which gives v 2 = 31 m/s .
5．what is the maximum speed with which a 1200-kg car can round a turn of radius on a flat road if the coefficient of friction between tires and road is ?Is this result independent of the
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1. A particle moves along the x axis. Its position as a function of time is given by x=+ 2, where t is in seconds and x is in meters. What is the acceleration as a function of time? Solution:
We find the velocity and acceleration by differentiating x = ( m/s)t + ( m/s 2)t 2:
v = d x /d t = ( m/s) + (17 m/s 2)t ;
a = d v /d t = 17 m/s 2.
2. What is the centripetal acceleration of a child
from the center of a merry-g