1 / 12
文档名称:

C语言程序设计:期末考试试卷(A卷).pdf

格式:pdf   大小:567KB   页数:12页
下载后只包含 1 个 PDF 格式的文档,没有任何的图纸或源代码,查看文件列表

如果您已付费下载过本站文档,您可以点这里二次下载

分享

预览

C语言程序设计:期末考试试卷(A卷).pdf

上传人:cjc201601 2023/3/27 文件大小:567 KB

下载得到文件列表

C语言程序设计:期末考试试卷(A卷).pdf

文档介绍

文档介绍:该【C语言程序设计:期末考试试卷(A卷) 】是由【cjc201601】上传分享,文档一共【12】页,该文档可以免费在线阅读,需要了解更多关于【C语言程序设计:期末考试试卷(A卷) 】的内容,可以使用淘豆网的站内搜索功能,选择自己适合的文档,以下文字是截取该文章内的部分文字,如需要获得完整电子版,请下载此文档到您的设备,方便您编辑和打印。:.
 
20 2

40

1C
AC
B!"#$%&'
CC()*+,-./01
DC2345
267C89:
AABCBabcCa_bcD>
3;C&'<
A;=&'>?***@A&'BC
BDEBC
C?***@F&BC
D?***@A&'BC
4;GHIJKL“7N4”P5;4 +QR4;4STUVW
ALX;YZ;[\
BLX;YZ;["
CL]4
D(/4
5^_`aab fcb idefb ghij10+'a'+i*fkElmbn
AintBfloatCdoubleD7N
6oCU charbElopqUqrsj
AtuBvuCwuDASCHu:.
7Lx&' [\Ely12345M678VcRzvCRh{|} xk
#include<>
main(){
intx;
floaty;
scanf(n%3d%f',&x,&y);
)
A12345B123C45D345
8^?LN~inta,b;floatx,g67k€
Aa=l,b=2
Bb++;
C>a=b=5
D^b=int(x);
9&'/‚ƒo
#include<>
(
inti=10,j=10;
printf(',%d,%d\n,,,++ij-);
)
A11,10B9,10C11,9D10,9
10…†‡ˆAASCHu65,&'/‚ƒ
#include<>:.
main()
charcl=A',c2=Y';
printfC'%d,%d\nM,cl,c2);
AA,YB65,65C65,90D65,89
11‰ŠG:U‹ŒŽ
A<B’C%D!=
12^xy>zintb_` –x=3,y=4,z=5,g—hijUkn0
A x'&& y'
Bx<=y
CxIIy+z&&y-z
D!(<x<y)&&!zII1)
13˜™charb_`clšn›œ‡ˆ67hijn
A^'a'<=cl<=f'z'B(cl>=a)&&(cl<=z)
C('a'>=cl)('z'<=cl)D(cl>='a')&&(cl<='z')
14‡:ž"a”opqUŸl‡ ;En
A0B1C2D3
15—L¡for¢£67ST
Afor¢£¤¥¦¢£§E¨©7Nª«
Bfor¢£Œ/¢£¬€ z˜Nhij
Cofor¢£U ¥break€­"¢£¬
Dfor¢£¬€U (®¯Z°€ ±²¥³´µ´¶·:.
16—&'Š/‚ƒ
#include<>
main()
{intnum=O;
while(num<=2)
{num++;
printf(44%d,num);
)
)
A1
B12
C123
D1234
17ST67
A<¦do-while¢£U¢£¬€¤°(/€ ¸¢£¬p¹¥
$º€
Bdo-while¢£<do»¼ ¥while‚½ owhile(hij)z—œ
µ
Codowhile¢£¬U N²L¹whilez—hijk_CX(“¾”)0
1
Ddowhile¢£U ¿lª«(ÀÁwhileo
18+ÂasEBa67ÃÄ
Ainta(10);Bintn=10,a[n];
C^intn;Dinta[10];:.
scanf("Åd”,&n);
inta[n];
19+ÆÂEBa67ÃÄ
Ainta[3][];Bfloata(3,4);
Cdoublea[lj[4];Dfloata(3)(4);
20?ÆÂEBaLm‰ goǗÈÉ;En
A^j*m+i
Bi*m+j
Ci*m+j-l
Di*m+j+l
Ê
ËÌÍ
(ÎÏÐ)
ÆÑÒ( 
10Ò Ò2

20
)
1,‚ÓÔ^ÕUÖ×Ø‚Ó
2oCUcb_`
nÙ×mb ÚÛÜ:.
3Þa=5,b=4,c=2æ hija>b!=ck
4‰&'Š/z["‚ƒ
#include<>
main()
(
inti,j;
for(i=4;i>=l;iù)
(printfC*");
for(j=1;j<=4-i;j++)
printfC*")
printf("\n");
)
)
5inta[3][4]={{l,2},{0},{4,6,8,10}}'()*+,,-.(/
01a23,-.(/04
65C67819:;<=>.?***@8.***@ABC04
,D
EFG
(HIJ):.
KLCDMNOPQNR2N1SN4D1R8D1TULCVWXYZLC[\]^_
1#include<>
main()
{inta,s,n,count;
a=2;s=0;n=1;count=l;
while(count<=7){n=n*a;s=s+n;++count;}
printf("s=%d",s);
)
2#include<>
main()
{inta=[3][3]={1,3,5,7,9,11,13,15,17},sum=O,i,j;
for(i=0;i<3;i++)
for(j=0;j<3;j++)
if(i=j)sum=sum+a[i][jj;
printf(<<sum=%d\n,,,sum);
)
,D
EF`
OHIJ_:.
abLNOPQNR4N1SN8D1R32D_
IbYdefghefgijLC4klmnopGqrdefg1stuvwxy
.hefg1pZz{|};4ij~F=OC+32_X9/54
2„bL…†pG.‡ˆ;0‰Š05‹07.‡;401'pZyes‰'pZno4
3…†;m0‰“>;O”W•1–—P˜ˆ™.ˆ;_š
4x15r;›\œC1m}-
žŸ8 ¡Q¢£¤¥OP¦_
§C67LC¨©ª«¬­„„FOAF_¯D°±²°±³´
qµ¶·¸NOPQNR20N1SN2D1R40D_
1B2D3B4B5C
6D7B8B9A10D
11C12D13D14C15D
16C17C18D19C20B:.
9»¼NOPQNR10¼1S¼2D1R20D_
1BC]½D¾]½¿À]½
2µÁgÂOÃfloatÂ_ÄÁgÂOÃdoubleÂÅ
31
4*
**
***
****
506
6\Æ******@A
KLCDMNOPQNR2N1SN4D1R8D_
W‡ÇÈÉZNÊ.Ëkl1ÌÍ,D1ÎD‡Ç͝ÏÐ,D,‰'Ñ,D4
1VW:lS=0+2+4+8+16+32+64+128–4
pZ]^s=254
2VWZÓÔÕa.ÆxÖ×Ø.=>ٖ4
pZ]^27
abLNOPQNR4N1SN8D1R32D_
W‡ÇÈÉZNÊ.Ëkl1ÚÛ‡Ç1ÌÍ,ÜD1ÑklÔÝIÞß4ÎD‡
Ç͝ÏÐ,D,‰'Ñ,D4
1#include<>
main
{floatc,f;:.
printf("inputc:n);........................................................................2D
scanf(M%f,,&c);........................................................................2D
f=(c+)*;........................................................................2D
printf(MF=%.2f\nn,0;.......................................................................2D
2#include<>
main()
{intx;
scanf(M%du,&x);........................................................................2D
if(x%5==0&&x%7==0)........................................................................2D
printf("yes”);........................................................................2D
else
printf("non);........................................................................2D
3#include<>
#include<>
main()
{intm,i,k;
scanf("àd\n",&m);:.
k=sqrt(m);.2D
for(i=2;i<=k;i++)........................................................................2D
{if(m%i==O)
break;........................................................................2D
)
if(i>k)
printf("misaprimenumber!\n");....................................................2D
)
4#include<>
main()
{inti,j,a[15],t;
printf("input15numbers:\nM);
for(i=0;i<15;i++)
scanf(u%dM,&a[i]);........................................................................2D
for(j=0;j<15;j++)........................................................................2D
for(i=0;i<15j;i++)........................................................................2D
if(a[i]>a[i+l])
{t=a[i];a[i]=a[i+1];a[i+l]=t;}.2D:.
for(i=0;i<15;i++)
printf(”à6d”,a[i]);