文档介绍：考研真题三时有且是恒大于零的可导函数设bxaxgxfxgxfxgxf??????,0)()()()(,)(),(3.);()()()(xgafagxf(B)?);()()()(xgbfbgxf(A)?00数二考研题填空xxxx????.)21ln(???????.???????)(xy??21e1/x00数二考研题则当出其类型求该函数的间断点并指记此极限为求极限.),(,??xfxtxtxxt01数二考研题)(,1)1()1(,)(,)1,1()(6.)3()1((A)ffxfxfxxy?????????则且严格单调减内有二阶导数在区间已知函数的拐点个数为曲线??;0(A);1(B);2(C).3(D);)()1,1()1,1(xxf???内均有和在??01数二考研题01数二考研题).((D)(C)(B);)()1,1()1,1(xxf???内均有和在??;)(,)1,1(,)(,)1,1(xxfxxf????内在内在??.)(,)1,1(,)(,)1,1(xxfxxf????内在内在??[])(lim(2);)()0()(),1,0()(,0)1,1((1):,0)()1,1()(?????????????xxxfxfxfxxxfxfyx???01数一考研题).3)(0(0)1ln()(4.)(2nfnxxxxfn????阶导数处的在求);()()()(bgbfxgxf(C)?).()()()(agafxgxf(D)?00数二考研题少则内具界且可导在设函数,),0()(9.???xfy;0)(lim,0)(lim?????????xfxf(A)xx必有时当02数一考研题( ).6...1lnln2,011..,,0)0()2()(,0)0(,0)0(0)(10..0)(lim,)(lim;0)(lim,0)(lim;0)(lim,)(lim220000?????????????????????????????????abababbaababahhfhbfhafffxxfxfxf(D)xfxf(C)xfxf(B)xxxxxx证明不等式设试确定高阶的无穷小时是比在若的某个邻域内具有一阶连续导数且在设函数必有存在时当必有时当必有存在时当02数一考研题02数二考研题的值?0)(),()1(?xfba内在;;)(2)(,),()2(22???bafdxxfabba???使内存在点在)2(),()3(ba??使相异的点中内存在与在)(),()(13两个极小值点和一个极大值点一个极小值点和两个极大值点有则内连续在设函数(B)(A)xfxf??.?其导,,?)(;;三个极小值点和一个极大值点两个极小值点和两个极大值点(D)(C);..______?lim0?xcosx)(ln()1x?????15.,),(,],[)(,)2()('????axaxax