文档介绍：内蒙古民族大学2012-2013学年二学期
课程考试试卷答案(B卷)
课程名称:普通化学和无机化学考试时间:120分钟年级:xxx级专业: xxx
题目部分,(卷面共有33题,100分,各大题标有题量和总分)
一、单项选择题(16小题,共28分)
11. A
二、填空(10小题,共27分)
1.(1) (2) (3) (4) (5)
二ⅣA
F F F
3s23p63d1
mol
6.(NO) = +90 kJ·mol-1
+,H+,SO3 Cl-
8., ,NH3 ,Ac- H2CO3,HAc
9.< > > =
sp2 sp3 sp3d
三、计算(6小题,共40分)
1.(1) Pt, Cl2()┃Cl- ( mol·dm-3)‖( mol·dm-3),
Mn2+ ( mol·dm-3), H+ ( mol·dm-3)┃Pt
(2) (+)极:+ 8H+ + 5e- = Mn2+ + 4H2O
(-)极:2Cl- = Cl2+ 2e-
电池反应:2+ 10Cl- + 16H+ = 2Mn2+ + 5Cl2 + 8H2O
=(+) -(-) = - = (V)
(3) = -= -10 ´ ´ = - ´ 102 (kJ/mol)
lg= / = (10 ´ ) / = ,= ´ 1025
(4) E =- () lg (1/[H+]16)
= + () (-32) lg10 = - (V)
(5) K不变。D rGm = -zFE = -10 ´ (-) = 38 (kJ·mol-1)
E = –
(H+/H2) == E += + (-) = - (V)
根据奈斯特方程:
(H+/H2) =(H+/H2) +lg [H+]2
- = +lg [H+]2
lg [H+] = - 所以 pH »
3.(1) 速率方程: v == k (CO)m (NO2)n
固定(CO), v 1 = k ()m ()n = ´ 10-4 v 3 = k ()m ()n = ´ 10-4
所以n = 1
固定(NO2), v 1 = k ()m ()n = ´ 10-4 v 2= k ()m ()n = ´ 10-4
所以m = 1
v = k (CO) (NO2)
(2) k650K == (dm3·mol-1·s-1)