文档介绍：Errata
Instructor’s Solutions Manual
Introduction to Electrodynamics, 3rd ed
Author: David Griffiths
Date: September 1, 2004
• Page 4, Prob. (b): last expression should read y +2z +3x.
• Page 4, : at the beginning, insert the following figure
• Page 8, Prob. : last line should read
2
From Prob. : ∇× va = −6xz xˆ+2z yˆ+3z ˆz ⇒
∇· ∇× ∂−∂∂ 2 −
( va)= ∂x( 6xz)+ ∂y (2z)+ ∂z (3z )= 6z +6z =0.
• Page 8, Prob. , in the determinant for ∇×(∇f), 3rd row, 2nd column:
change y3 to y2.
• Page 8, Prob. , line 2: the number in the box should be -12 (insert
minus sign).
• Page 9, Prob. , line 2: change 2x3 to 2z3; first line of part (c): insert
comma between dx and dz.
• Page 12, Probl , line 5: ma after cos θ.
• Page 13, Prob. (c), last line: insert ˆz after ).
• Page 14, Prob. (b): change r to a.
• Page 14, Prob. , second line of J: change the upper limit on the r
integral from ∞ to R. Fix the last line to read:
−−r R −R −−R −0 −R
=4π e 0 +4πe =4π e + e +4πe =4π.
• Page 15, Prob. (a), line 3: in the box, change x2 to x3.
1
• Page 15, Prob. (b), last integration “constant” should be l(x, z), not
l(x, y).
• Page 17, Prob. , first expression in (4): insert θ,soda = r sin θdrdφθˆ.
• Page 17, Prob. : Solution should read as follows:
Problem
(1) x = z =0; dx = dz =