文档介绍：图2-14破裂面示意图等代土层厚度h1(汽-20重车作用下):(1)计算荷载布置长度B已知汽—20重车的前后轴距L=+=,车轮接地长度a=,由规范得:??????因为挡土墙分段长度大于10m,故取扩散长度B=(2)计算荷载布置宽度0La)按活动区宽度布置汽车荷载求)1(h??KNG300,0L=,B=,3/18mKN??。按路基全宽布置汽车荷载求)2(h因路面宽为22m,除去隔离带宽度,可布置6辆重车????KNG18003006,mL220?,B=,3/18mKN??)2(?????)1()2(hh??,故取mL220?且沿全路基宽布置六行车队取h1=)(11???????)1(????。。=2)2(1hHKHa???=???=(KN)从控制墙身变形出发,进行墙身宽度B的初步设计,从而得到:441124])(2)[cos(125ExxhHKBa????????=,进行墙身宽度的进一步设计,分为墙身抗滑和墙身抗倾覆两种情况。假设各层拉筋的锚固长度均为mL。(3)根据墙身抗滑,确定21BHEKLfxHHEKHEKLxfnnEKByfmxcymxc??????????????????1121][)1(][][)1(][????????=-?????????????L)(=?(m)当mL=,21B==,21B==,21B==,21B=(4)根据墙身抗倾覆,确定22BHKxxHLHfKHEHEHEHBfmExEyy?????????????1220122122]][3)(][)tan([2)2)tan((??????HEHy?????1212)tan(???=)(????mL(m)当mL=,22B==,22B==,22B=2m墙身宽度B减为2m,。L=Lm+Lh第一层加筋长度L=+==+==+==+==+=。验算部分:第二步:稳定性验算(1)墙底偏心距验算NMMBey?????0'2yniExiEyGEGHExinTHEGHB??????????1)1(2=??B(2)基底偏心距e和基底应力验算001'0000)()2)((22GEGbTEeBaEGBaGBaeyniixy??????????????=??=(m)2100100max)()(6BaeGEGBaGEGyy?????????=?