通信电子线路-(谢沅清-邓钢-著)-电子工业出版社-课后答案-2.pdf

文档介绍：ƒ  e

/¶‚xÖ 3Ÿ$Ÿ‰7g

Òl 2-3 a  à ƹ ó L = 4 H  C = 400 pF üäe[X Q 
 100 U`Ôþ5 ¹U²ÃXÝQ  Bn `
5 10 t) mA Q 50 C1
C X JukgÎ _
2 Òl
5 2-4
·  is X<ãùµËe[ f0=5 10 Hz ä
²Ã 
CC 1
C ==12
CC+ 4π22fL
12 0 1
1
=≈510×3 pF
4π×2 5 2 × 10 10 × 100 × 10− 6
²ÃMûk
ρ = LC/

课后答案网=×100 10−−69 / 5 ×=Ω 10 140
SÝQ Q  50 ²ÃøÃÝ 
RQ==×=ρ 50 140 7000 Ω
lÜDzÃøÃX  â J(X bÝ
RL 'L Rs R
RR 730×
R′ ===Ω5 k
L −−
RR5 30 7
y9ÏD hµ‡
pc
CR5