文档介绍：线性代数第六版课后习题详解答案线性代数课后习题解答第一章习题详解篇一::21abc111c;(4)c2xyx?yyx?yxx?yxy(1)1?4?1;(2)bca;(3)ab22?(1)1?4?1?2?(?4)?3?0?(?1)?(?1)?1?1?8?0?1?3?2?(?1)?8?1?(?4)?(?1)?183=?24?8?16?4=?4abc(2)bca?acb?bac?cba?bbb?c?3abc?a3?b3?c3cab11(3)ab22abx1c?bc2?ca2?ab2?ac2?ba2?cb2?(a?b)(b?c)(c?a)2cyx?yx(4)yx?yx?y333x?x(x?y)y?yx(x?y)?(x?y)yx?y?(x?y)?xy?3xy(x?y)?y?3xy?3yx?x?y?x??2(x?y),求下列各排列的逆序数:(1)1234;(2)4132;(3)3421;(4)2413;(5)13…(2n?1)24…(2n);(6)13…(2n?1)(2n)(2n?2)…(1)逆序数为0(2)逆序数为4:41,43,42,32(3)逆序数为5:32,31,42,41,21(4)逆序数为3:21,41,43(5)逆序数为n(n?1)2:321个52,542个72,74,763个…………………(2n?1)2,(2n?1)4,(2n?1)6,…,(2n?1)(2n?2)(n?1)个(6)逆序数为n(n?1)321个52,542个…………………(2n?1)2,(2n?1)4,(2n?1)6,…,(2n?1)(2n?2)(n?1)个421个62,642个…………………(2n)2,(2n)4,(2n)6,…,(2n)(2n?2)(n?1),四阶行列式的一般项为(?1)a1p1a2p2a3p3a4p4,?1,p2?3已固定,p1p2p3p4只能形如13□□,?0?1?0?1或0?0?0?2?2t??:?4?1(1)??10??0解410124??21?3?1202??;(2)?520??12117????50124202c2?c341???ab21??;(3)?bd?32??bf62??ac?cdcf10?aae???1b1?de;(4)???0?1c?ef?0?1??00?0??1?d??41?12?1023024?1?10232?14?(?1)4?34?11023?214(1)520c4?7c31170c2?c3c1?2=12?14109010?2=01440r4?r2=190c3172120212041c4?c22121214030402120403000(2)3?1211532623?1221530623?122r4?r13?12210=0?abac?cdcf1b?1001caede?ef00r1?ar21?0e?ea1c001?111?1111=4abcdef?1(3)bdbfa=adfbbe=adfbce11?abb?10(4)?100?100?abac01=(?1)(?1)2?1?10?1d?1d?ab?1ad1?cd?1dc3?dc2?ab?10ac?1ad1?cd=(?1)(?1)3?2=abcd?ab?cd?ad?1a2abb2ax?byay?bzaz?bxax?byaz?bx33xz