供电技术 第四版 余建明 课后答案资料[2-4章].pdf

文档介绍：2-1
2-2
2-3
2-4 Tmax
Tmax
Pmax Tmax
Wa
2-5
1.
2.
3.
4.
5.
6.
7.
8.
9.
2-6
100%
50% 70%
2-7
15%~20%
2-8
2-9
2-10
2-11 10 6 kV 3
10 6 Yyn0 Dyn11
Dyn11
2-12
100V
2-13
2-14
1
2
2-15
1
10kV
10kV
2
3
4
1 20%
2
3
FCn/ FC 15%/25%
FCn/ FC 66%/100%

3
2-18 (1)

3
=1792kvar
Pc1 PK nd 00 kwkw
Qc Pc11 an k ar 67v k var5.
Pc2 PK nd kw kw
Qc Pc22 an k ar 554v k var4.
Pc3 PK nd 700 kw kw
Qc Pc33 an ar 168v kk var
Pc4 PK nd kw kw
Qc Pc44 an ar 225v kk var
=
(PcKPc PcPcPc 4321 kw 1962)300350630900() kw
QcQcQcQcKQc 4321 ( k ar) 1640v k var
Sc 22 cQcP KVA
cos Pc Sc /
B1 PcQ (tan 1 an 2 (1962)t ar) ar 530v 530530r kk vara
1 QcQc QB1 ********** k var
Sc 22 cQcP 2252KVA
2-22 I30=128A
LJ-95
R0= /kmX0= /km
2
I 2
PL=3 30 R=3 128
2
I 2
3 30 X=3 128