文档介绍：习题答案
逻辑代数基础
0-1
(1) 11 (2) 27
(3)
(4)
0-2
(1)
(100100) 2
(2) (1100000)
2 (3) (1111101) 2(4) () 2
0-3
(1)
(110110) 2
(2) (101101000111100) 2
(3)
() 2
(4) () 2
0-4
(1)
(33) i6
(2) (1AD3) 16
(3)()16 (4)(63.! A) l6
0-5 (1) (11111010) 2>(F9)i6>(37O)8>(OO1OO1OOO111)842ibcd>(246)io
0-6 (1)(1001) 8421BCD (2)(00011001) 8421BCD
() 8421BCD
(**********) 8421 BCD
0-7 (1)(10010)2 (2)(110001), (3)()2 (4)(--)2
0-8 (1) Y=1 (2)Y=0 (3)Y=1
0-9 (l)A=B=0 C=1;B=C=1 A=0;A=B=l C=0;A=B=C=l
A=B=C=0;A=B=0 C=l;A=C=0 B=l;B=C=0 A=1
A=B=C=0;A=C=0 B=1;B=C=1 A=0;B=C=0 A=l;
A=C=1 B=0;A=B=l C=0
A=0 B=C=1;A=1 B=C=0;A=C=l B=0
0-10 略
o-ii (1)= A(s + c)(c+r))
Y' = (A + B + C)(A + B + D\A + C + D)
Y' = (A + B)(B + D)(C + D + E)(A + D)
Y' = A + B + C + BC
0-12 (1) Y AB + AC DE
Y =^B + ACD + ACE
Y = ACDE + BCDE + AB
Y =A+C
(3) Y=AB
0-13 (1) Y^~AB + D (2) A + BC + BC+BD
(4) Y = AB + D + C
0-14 略
0-15 (a) Y = AB+AD + BC + CD (b) Y = BD + ACD + ABC + ABC + ACD
0-16 (1) Y = B
Y = ACD + ABD + ABD + ~ACD
Y = AB-^BC + AD
Y = A + D +BC
0-17 (1) Y = AB+ BC +AC
Y = AB + AB+ BC
y = ABCD + CD + AC + BC
Y = CD + BD +AD
Y = BD +BD + BC
7 = AB + BCD + AD + AC
0-18 略
0-19 (1) y = B + C (2) Y = B + C +AD (3) y = BD + CD + BD
(4) 7 = CD + B