文档介绍：vO
+VCC
T1
T2
+
Re3
Re6
RL
_
-V
+
_
RC
vI
EE
T3
T4
T5
T6
Rc4
680
350
150
10K
10V
-10V
例2 :=100,rbb‘=100,静态时vo=0V
(1)计算静态电流
(2)计算差模放大倍数
例3:电路如图,静态时,Vo=0。求R=?
T5
T6
T3
T4
R8
R9
R3
10K
R4
10K
R5
R2
1M
R6
6K
R7
6K
R
vi
+15V
-12V
T1
T2
R1
1M
vo
解:(1)静态分析:
IC3=IC4=2mA
VR5=2 IC4 R5
=
VR3=VR4
= VR5+VBE3 =
ID1=ID2=
VR8= VR9 = 2 ID2 R8
=
VR=12-- VR8
=
IR9= VR8 / R9 =
R= VR / IR9 =
T5
T6
T3
T4
R8
R9
R3
10K
R4
10K
R5
R2
1M
R6
6K
R7
6K
R
vi
+15V
-12V
T1
T2
R1
1M
vo
设=150,gm=3mA/V,rbe3=rbe4=
输入输出同相
T5
T6
T3
T4
R8
R9
R3
10K
R4
10K
R5
R2
1M
R6
6K
R7
6K
R
vi
+15V
-12V
T1
T2
R1
1M
vo