文档介绍：第一学期《无机化学》期终考试试卷答案(B)
1-8章
一、选择题( 共16题 16分)
1. (3972) (D)
2. (3675) (C)
3. (0974) (D)
4. (6673) (D)
5. (0672) (D) 盐效应使溶解度加大
6. (3971) (C)
7. (3418) (C)
8. (0617) (D)
9. (3693) (B)
10. (3793) (B)
11. (3439) (B)
12. (0777) (A)
13. (0975) (A)
14. (3674) (C)
15. (3333) (B)
16. (0972) (B)
二、填空题( 共 6题 14分)
1. (3746) (1) ,。(2) Cl2,Fe3+,Ag+。(3) 无。
2. (0674) 减小,增大,小
3. (0675) 增大,变小,变大,不变
4. (6760)Ni(OH)3(s) + e- = Ni(OH)2(s) + OH-(aq) ;Cd(s) + 2OH-(aq) = CdO(s) + H2O(l) + 2e-
5. (0447) ΔG < 0 为- ΔS > 0 为+
6. (0710) (1) > (4) > (2) > (3)
三、计算题( 共 4题 32分[8,8,8,8] )
1. (0523)
设PCl3的转化率为x
PCl3 + Cl2 PCl5
达平衡时物质的量/mol (-x) (-x)  x
物质的总量= (-x) mol
kPa kPa
==
解得 x =
=
=
2. (3704)
(1) 5HBrO =+ 2Br2 + 2H2O + H+
(2) = - = V
= -= -4 ´ ´ = -39 (kJ·mol-1)
(3) = - lgK
lgK ==
所以 K » ´ 106
3. (3333)Solution.
Calculation of [Ag+] at the point where AgCl precipitation starts:
Ksp(AgCl) = [Ag+][Cl-] = * 10-10
so [Ag+] = Ksp/[Cl-] = * 10-10/ = * 10-9 M
Calculation of [Br-] consistent with this [Ag+]:
Ksp(AgBr) = [Ag+][Br-] = 5 * 10-13
so [Br-] = Ksp(AgBr)/[Ag+] = 5 * 10-13/( * 10-9)
= * 10-4 M
According to this calculation, we can reduce the concentrat