文档介绍：数学实验报告学院:电力学院班级:2014级电气3班学号:201430224138姓名:游渊完成日期:。。。(1)画出部分和数列{Sn}变化的折线图,观察变化规律;(2)引入数列{Hn}:Hn=S2n–Sn,作图观察其变化,猜测是否有极限(3)引入数列{Gn}:Gn=S2n,作图观察其变化,寻找恰当的函数拟合;(4)讨论部分和数列{Sn}的变化规律。,代码如下:functionshulie1(n)sn=[1];fori=2:n;sn=[sn,sn(i-1)+1/i];endplot(sn)n=1000,=S2n-Sn,进行数列计算,代码如下:functionshulie2(n)sn=[1];fori=2:2*n;sn=[sn,sn(i-1)+1/i];endDn=sn(2)-sn(1);fort=2:nDn=[Dn,sn(2*t)-sn(t)];endplot(Dn)令n=1000,图像为可判断数列有极限,=S2^n,代码如下:functionshulie3(n)sn=[1];fori=2:2*n;sn=[sn,sn(i-1)+1/i];endTn=sn(2);fort=2:nTn=[Tn,sn(2*t)];endplot(Tn)对函数进行线性拟合:functiony=shulie4(n)Tn=[];fori=2:nTn=[Tn,Tn(i-1)+1/(2*i)+1/(2*i-1)];endn=1:n;Tn=exp(Tn);y=polyfit(xn,Tn,1)进行一阶拟合的结果为shulie4(1000)Y==,代码为:functiony=shulie5(n)Tn1=[];fori=1:nTn1=[Tn1,log(*i+)];endTn2=[];fori=2:nTn2=[Tn2,Tn2(i-1)+1/(2*i)+1/(2*i-1)];endx=1:n;plot(x,Tn1,'b',x,Tn2,'r*')取shulie5(100)导出的图像为:观测可知,函数拟合程度较好,可近似认为Sn=*log2(n)+。。。。问题描述以年份为横坐标y,以人口数量为纵坐标p进行人口数量曲线的图像绘制:yi=1990:2010;p1=[114333,115823,117171,118517,119850,121121,122389,123626,124761,125786];pi=[p1,126743,127627,128453,129227,129988,130756,131448,132129,132802,133450,134091];plot(yi,pi)进行一次多项式的拟合:yi=1990:2010;p1=[114333,115823,117171,118517,119850,121121,122389,123626,124761,125786];pi=[p1,126743,127627,128453,129227,129988,130756,131448,132129,132802,133450,134091];k1=polyfit(yi,pi,1)y=1990::2010;y=polyval(k1,y);plot(yi,pi,'r.',y,p)拟合结果误差较大,重新对该函数的二次多项式的拟合:yi=1990:2010;p1=[114333,115823,117171,118517,119850,121121,122389,123626,124761,125786];pi=[p1,126743,127627,128453,129227,129988,130756,131448,132129,132802,133450,134091];k1=polyfit(yi,pi,2)x=1990::2010;y=polyval(k1,y);plot(yi,pi,'r.',y,p)二次拟合情况较好,基本可以该函数作为人口数量发展规律的拟合。得K1=--