文档介绍:
西工大NOJ101题+解答
#include<> int main() {
int a,b,sum;
scanf(%d%d,a,b); sum=a+; }
#include<> int main() {
int n;
scanf(%d,n);
if ((1010<n<10100)(n/1010==n%10)(n/101%10==n/10%10)) printf(yes\n); else if((101<n<=1010)(n/101==n%10)) printf(yes\n); else if((10<n<=101)(n/10==n%10)) printf(yes\n); else if(0<n<=10) printf(yes\n); else printf(no\n); return 0; }
#include<> int main() {
double l,bon; scanf(%lf,l); if(l<=10) bon=l*;
else if(l<20) bon=1+(l-10)*; else if(l<40) bon=+(l-20)*; else if(l<60) bon=+(l-40)*; else if(l<101) bon=+(l-60)*; else bon=+(l-101)*; printf(%lf\n,bon); return 0; }
#include<> int main() {
double d,m; scanf(%lf,d); if(d<=2) m=7; else if(d<=15){
if(d-2==(int)(d-2)) m=7+(d-2)*; else m=7+((int)(d-2)+1)*; }
else if(d-15==(int)(d-15)) m=+(d-15)*; else m=+((int)(d-15)+1)*; printf(%lf\n,m); return 0; }
#include<> int main() {
int y,m,d,Days,sum;
scanf(%d-%d-%d,y,m,d);
if((y%4==0y%101!=0)||(y%400==0)) Days=29; else Days=28; switch(m){
case 1:sum=