文档介绍：整式训练专题训练
1归纳出去括号的法则吗?
2. 去括号:
(1)a+(-b+c-d); (2)a-(-b+c-d) ;
(3)-(p+q)+(m-n); (4)(r+s)-(p-q).
?若有错,请改正:
(1)a2-(2a-b+c) (2)-(x-y)+(xy-1)
=a2-2a-b+c; =-x-y+xy-1.
(3)(y-x) 2 =(x-y) 2
(4) (-y-x) 2 =(x+y) 2
(5) (y-x)3 =(x-y) 3
:
(1)(2x-3y)+(5x+4y); (2)(8a-7b)-(4a-5b);
(3)a-(2a+b)+2(a-2b); (4)3(5x+4)-(3x-5);
(5)(8x-3y)-(4x+3y-z)+2z; (6)-5x2+(5x-8x2)-(-12x2+4x)+2;
(7)2-(1+x)+(1+x+x2-x2); (8)3a2+a2-(2a2-2a)+(3a-a2)。
作业:
,在___上填上“+”号或“-”号:
(1) a___(-b+c)=a-b+c; (2)a___(b-c-d)=a-b+c+d;
(3) ___(a-b)___(c+d)=c+d-a+b
+y=2,则x+y+3= ,5-x-y= .
:
(1)a+3(2b+c-d); (2)3x-2(3y+2z).
(3)3a+4b-(2b+4a); (4)(2x-3y)-3(4x-2y).
:
(1)2a-3b+[4a-(3a-b)]; (2)3b-2c-[-4a+(c+3b)]+c.
拔高题:
1. 化简2-[2(x+3y)-3(x-2y)]的结果是( ).
+2; -12y+2; C.-5x+12y+2; -5x.
2. 已知:+=3,求{x-[x2-(1-x)]}-1的值.
,与a-b-c的值不相等的是( )
-(b+c) -(b-c)
C.(a-b)+(-c) D.(-c)+(-b+a)
-[0-(2p-q)]的结果是( )
A.-2p-q B.-2p+q -q +q
,正确的是( )
-(2b-3c)=a-2b-3c
-(3x2+2x-1)=x3-3x2-2x-1
+(-2y+1)=2y2-2y+1
D.-(2x-y)-(-x2+y2)=-2x+y+x2+y2
:
a+(b-c)= ; (a-b)+(-c-d)= ;
-(a-b)-(-c-d)= ;
5x3-[3x2-(x-1)]= .
.
(1)x-(y-z)=x-y-z ( )
(2)-(x-y+z)=-x+y-z ( )
(3)x-2(y-z)=x-2y+z ( )
(4)-(a-b)+(-c-d)=-a+b+c+d ( )
:
-(2m-3); n-3(4-2m);
(1) 16a-8(3b+4c); (2) -(x+y)+(p+q);
(3)-8(3a-2ab+4); (4) 4(rn+p)-7(n-2q).
(5)8